What is the general solution for 2csc(2x)cot(2x)=0 ?

The general solution for 2csc(2x)cot(2x)=0 is x= pi/4+(pin)/2

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2csc(2x)cot(2x)=0

2 csc (2 x) cot (2 x) = 0

x = \frac{π}{4} + \frac{πn}{2}

Solution steps

2 csc (2 x) cot (2 x) = 0

Solving each part separately

csc (2 x) = 0 or cot (2 x) = 0

csc (2 x) = 0 :

No Solution

cot (2 x) = 0 : x = \frac{π}{4} + \frac{πn}{2}

Combine all the solutions

x = \frac{π}{4} + \frac{πn}{2}

3 cos (y) + cot (y) = 0

2 sin (x) - 3 sin (x) + 1 = 0

2 sin (x) (sin (x) - 1) = 3 cos^{2} (x)

2 sin^{2} (x) = 2 sin (x) + 4

sin (x) cos^{2} (x) = sin (x), 0 \leq x \leq 2 π

What is the general solution for 2csc(2x)cot(2x)=0 ?
The general solution for 2csc(2x)cot(2x)=0 is x= pi/4+(pin)/2