What is the general solution for cos(9x)= 1/2 ?

The general solution for cos(9x)= 1/2 is x= pi/(27)+(2pin)/9 ,x=(5pi}{27}+\frac{2pin)/9

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cos(9x)= 1/2

cos (9 x) = \frac{1}{2}

x = \frac{π}{27} + \frac{2 πn}{9}, x = \frac{5 π}{27} + \frac{2 πn}{9}

Solution steps

cos (9 x) = \frac{1}{2}

General solutions for

cos (9 x) = \frac{1}{2}

9 x = \frac{π}{3} + 2 πn, 9 x = \frac{5 π}{3} + 2 πn

Solve

9 x = \frac{π}{3} + 2 πn : x = \frac{π}{27} + \frac{2 πn}{9}

Solve

9 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{27} + \frac{2 πn}{9}

x = \frac{π}{27} + \frac{2 πn}{9}, x = \frac{5 π}{27} + \frac{2 πn}{9}

tan (2 θ) = - 3, 0^{\circ} \leq θ \leq 36 0^{\circ}

0 = tan (c)

cos (t) - cos (2 t) = 0

4 sin (θ) = - 2 cos (θ)

cot (2 x) = - 1, (0, 2 π)

What is the general solution for cos(9x)= 1/2 ?
The general solution for cos(9x)= 1/2 is x= pi/(27)+(2pin)/9 ,x=(5pi}{27}+\frac{2pin)/9