What is the general solution for tan^2(2θ)=3 ?

The general solution for tan^2(2θ)=3 is θ= pi/6+(pin)/2 ,θ= pi/3+(pin)/2

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tan^2(2θ)=3

tan^{2} (2 θ) = 3

θ = \frac{π}{6} + \frac{πn}{2}, θ = \frac{π}{3} + \frac{πn}{2}

Solution steps

tan^{2} (2 θ) = 3

Solve by substitution

tan (2 θ) = 3, tan (2 θ) = - 3

tan (2 θ) = 3 : θ = \frac{π}{6} + \frac{πn}{2}

tan (2 θ) = - 3 : θ = \frac{π}{3} + \frac{πn}{2}

Combine all the solutions

θ = \frac{π}{6} + \frac{πn}{2}, θ = \frac{π}{3} + \frac{πn}{2}

tan^{2} (2 θ) = 1

(50.691) cos (50.69 1^{\circ} - c) + sin (50.69 1^{\circ} - c) = 0

sec (4 θ) = 2

tan^{2} (x) - 4 tan (x) + 1 = 0

sec (θ) + cos (θ) = sin (θ) tan (θ)

What is the general solution for tan^2(2θ)=3 ?
The general solution for tan^2(2θ)=3 is θ= pi/6+(pin)/2 ,θ= pi/3+(pin)/2