What is the general solution for sin(x)-cos^2(x)=sin^2(x) ?

The general solution for sin(x)-cos^2(x)=sin^2(x) is x= pi/2+2pin

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sin(x)-cos^2(x)=sin^2(x)

sin (x) - cos^{2} (x) = sin^{2} (x)

x = \frac{π}{2} + 2 πn

Solution steps

sin (x) - cos^{2} (x) = sin^{2} (x)

Subtract

sin^{2} (x)

from both sides

sin (x) - cos^{2} (x) - sin^{2} (x) = 0

Rewrite using trig identities

sin (x) - 1 = 0

Move

1

to the right side

sin (x) = 1

General solutions for

sin (x) = 1

x = \frac{π}{2} + 2 πn

cos^{4} (x) = 1 + sin^{4} (x)

- 4 cos^{2} (θ) - 11 cos (θ) - 1 = - 7 cos (θ)

0 = 1 + cos (\frac{x}{2})

sin (x) = cos (1 9^{\circ})

\frac{1}{1.5} = \frac{sin ( 3 0 ^{\circ} )}{sin ( x )}, x < 9 0^{\circ}

What is the general solution for sin(x)-cos^2(x)=sin^2(x) ?
The general solution for sin(x)-cos^2(x)=sin^2(x) is x= pi/2+2pin