What is the general solution for sin(2x)=-1/(sqrt(2)) ?

The general solution for sin(2x)=-1/(sqrt(2)) is x=(5pi)/8+pin,x=(7pi)/8+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(2x)=-1/(sqrt(2))

sin (2 x) = - \frac{1}{2}

x = \frac{5 π}{8} + πn, x = \frac{7 π}{8} + πn

Solution steps

sin (2 x) = - \frac{1}{2}

Simplify

- \frac{1}{2} : - \frac{2}{2}

General solutions for

sin (2 x) = - \frac{2}{2}

2 x = \frac{5 π}{4} + 2 πn, 2 x = \frac{7 π}{4} + 2 πn

Solve

2 x = \frac{5 π}{4} + 2 πn : x = \frac{5 π}{8} + πn

Solve

2 x = \frac{7 π}{4} + 2 πn : x = \frac{7 π}{8} + πn

x = \frac{5 π}{8} + πn, x = \frac{7 π}{8} + πn

cos (x) = - \frac{22}{7.28 \cdot 20}

sec^{2} (x) = 4 tan (x)

x, 1 + sin (2 x - 3 0^{\circ}) = 0

cos (x^{2}) = sin (x^{2})

\frac{cos ( - x )}{sin ( x )} = 0

What is the general solution for sin(2x)=-1/(sqrt(2)) ?
The general solution for sin(2x)=-1/(sqrt(2)) is x=(5pi)/8+pin,x=(7pi)/8+pin