What is the general solution for 6cos(θ)=3sqrt(2) ?

The general solution for 6cos(θ)=3sqrt(2) is θ= pi/4+2pin,θ=(7pi)/4+2pin

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6cos(θ)=3sqrt(2)

6 cos (θ) = 32

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

Degrees

θ = 4 5^{\circ} + 36 0^{\circ} n, θ = 31 5^{\circ} + 36 0^{\circ} n

Solution steps

6 cos (θ) = 32

Divide both sides by

6

6 cos (θ) = 32

Divide both sides by

6

\frac{6 cos ( θ )}{6} = \frac{3 2}{6}

Simplify

cos (θ) = \frac{2}{2}

cos (θ) = \frac{2}{2}

General solutions for

cos (θ) = \frac{2}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

2 cos^{2} (x) + sin (- x) - 3 = 0

376 = 80 \cdot 24.7 \cdot cos (x)

0 = arctan (t)

tan^{2} (x) = 1 + tan (x)

t, y = 3 sin (2 t - \frac{π}{4})

What is the general solution for 6cos(θ)=3sqrt(2) ?
The general solution for 6cos(θ)=3sqrt(2) is θ= pi/4+2pin,θ=(7pi)/4+2pin