What are the solutions to the equation (s^2+1)=0 ?

The solutions to the equation (s^2+1)=0 are s=i,s=-i

Find the zeros of (s^2+1)=0

The zeros of (s^2+1)=0 are s=i,s=-i

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(s^{2} + 1) = 0

s = i, s = - i

Solution steps

(s^{2} + 1) = 0

s^{2} + 1 = 0

Move

1

to the right side

s^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

s = - 1, s = - - 1

- 1 = i

- - 1 = - i

s = i, s = - i

- 3 x^{2} + 12 x - 12 = 0

8 x^{2} + 14 x + 40 = 7 x^{2}

x^{2} + 2 a x + a^{2} = 0

- x^{2} + 6 x - 8

(9 z + \frac{1}{2})^{2} + 61 = 39

What are the solutions to the equation (s^2+1)=0 ?
The solutions to the equation (s^2+1)=0 are s=i,s=-i
Find the zeros of (s^2+1)=0
The zeros of (s^2+1)=0 are s=i,s=-i