What are the solutions to the equation -3x^2+12x-12=0 ?

The solutions to the equation -3x^2+12x-12=0 are x=2

Find the zeros of -3x^2+12x-12=0

The zeros of -3x^2+12x-12=0 are x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 3 x^{2} + 12 x - 12 = 0

x = 2

Solution steps

- 3 x^{2} + 12 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 3 ) ( - 12 )}{2 ( - 3 )}

1 2^{2} - 4 (- 3) (- 12) = 0

x_{1, 2} = \frac{- 12 \pm 0}{2 ( - 3 )}

x = \frac{- 12}{2 ( - 3 )}

\frac{- 12}{2 ( - 3 )} = 2

x = 2

The solution to the quadratic equation is:

x = 2

8 x^{2} + 14 x + 40 = 7 x^{2}

x^{2} + 2 a x + a^{2} = 0

- x^{2} + 6 x - 8

(9 z + \frac{1}{2})^{2} + 61 = 39

- 40 m^{2} + 10 m - 1 = 0

What are the solutions to the equation -3x^2+12x-12=0 ?
The solutions to the equation -3x^2+12x-12=0 are x=2
Find the zeros of -3x^2+12x-12=0
The zeros of -3x^2+12x-12=0 are x=2