What are the solutions to the equation v^2-9v+14=0 ?

The solutions to the equation v^2-9v+14=0 are v=7,v=2

Find the zeros of v^2-9v+14=0

The zeros of v^2-9v+14=0 are v=7,v=2

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v^{2} - 9 v + 14 = 0

v = 7, v = 2

Solution steps

v^{2} - 9 v + 14 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 14 = 5

v_{1, 2} = \frac{- ( - 9 ) \pm 5}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 9 ) + 5}{2 \cdot 1}, v_{2} = \frac{- ( - 9 ) - 5}{2 \cdot 1}

v = \frac{- ( - 9 ) + 5}{2 \cdot 1} : 7

v = \frac{- ( - 9 ) - 5}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

v = 7, v = 2

s, h (s) = - 16 s^{2} + 80 s

a = x^{2} - 18 x + 80

x^{2} + 8 x + 16 = 16

x, y = x^{2} - 2 x - 3

u^{2} - 4 u + 4 = 0

What are the solutions to the equation v^2-9v+14=0 ?
The solutions to the equation v^2-9v+14=0 are v=7,v=2
Find the zeros of v^2-9v+14=0
The zeros of v^2-9v+14=0 are v=7,v=2