What are the solutions to the equation t^2+10t+9=0 ?

The solutions to the equation t^2+10t+9=0 are t=-1,t=-9

Find the zeros of t^2+10t+9=0

The zeros of t^2+10t+9=0 are t=-1,t=-9

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t^{2} + 10 t + 9 = 0

t = - 1, t = - 9

Solution steps

t^{2} + 10 t + 9 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 9 = 8

t_{1, 2} = \frac{- 10 \pm 8}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 10 + 8}{2 \cdot 1}, t_{2} = \frac{- 10 - 8}{2 \cdot 1}

t = \frac{- 10 + 8}{2 \cdot 1} : - 1

t = \frac{- 10 - 8}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

t = - 1, t = - 9

11 x^{2} - 153 x - 180 = 0

a^{2} + a + 1 = 0

\frac{c ^{2}}{8} - 3 = 2

x (2 x - 3) = 20

2 = 4 - 8 x^{2} + 4 x^{2} - 5 x - 2 - 3 x + 8 x^{2} - 4 x

What are the solutions to the equation t^2+10t+9=0 ?
The solutions to the equation t^2+10t+9=0 are t=-1,t=-9
Find the zeros of t^2+10t+9=0
The zeros of t^2+10t+9=0 are t=-1,t=-9