What are the solutions to the equation a^2+a+1=0 ?

The solutions to the equation a^2+a+1=0 are a=-1/2+i(sqrt(3))/2 ,a=-1/2-i(sqrt(3))/2

Find the zeros of a^2+a+1=0

The zeros of a^2+a+1=0 are a=-1/2+i(sqrt(3))/2 ,a=-1/2-i(sqrt(3))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

a^{2} + a + 1 = 0

a = - \frac{1}{2} + i \frac{3}{2}, a = - \frac{1}{2} - i \frac{3}{2}

Solution steps

a^{2} + a + 1 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 1 : 3 i

a_{1, 2} = \frac{- 1 \pm 3 i}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 1 + 3 i}{2 \cdot 1}, a_{2} = \frac{- 1 - 3 i}{2 \cdot 1}

a = \frac{- 1 + 3 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{3}{2}

a = \frac{- 1 - 3 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

a = - \frac{1}{2} + i \frac{3}{2}, a = - \frac{1}{2} - i \frac{3}{2}

\frac{c ^{2}}{8} - 3 = 2

x (2 x - 3) = 20

2 = 4 - 8 x^{2} + 4 x^{2} - 5 x - 2 - 3 x + 8 x^{2} - 4 x

x^{2} + (3 a - 2 b) x - 6 ab = 0

120 x - 4.5 x^{2} = 0

What are the solutions to the equation a^2+a+1=0 ?
The solutions to the equation a^2+a+1=0 are a=-1/2+i(sqrt(3))/2 ,a=-1/2-i(sqrt(3))/2
Find the zeros of a^2+a+1=0
The zeros of a^2+a+1=0 are a=-1/2+i(sqrt(3))/2 ,a=-1/2-i(sqrt(3))/2