What are the solutions to the equation 11x^2-153x-180=0 ?

The solutions to the equation 11x^2-153x-180=0 are x=15,x=-12/11

Find the zeros of 11x^2-153x-180=0

The zeros of 11x^2-153x-180=0 are x=15,x=-12/11

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11 x^{2} - 153 x - 180 = 0

x = 15, x = - \frac{12}{11}

Solution steps

11 x^{2} - 153 x - 180 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 153 ) \pm ( - 153 ) ^{2} - 4 \cdot 11 ( - 180 )}{2 \cdot 11}

(- 153)^{2} - 4 \cdot 11 (- 180) = 177

x_{1, 2} = \frac{- ( - 153 ) \pm 177}{2 \cdot 11}

Separate the solutions

x_{1} = \frac{- ( - 153 ) + 177}{2 \cdot 11}, x_{2} = \frac{- ( - 153 ) - 177}{2 \cdot 11}

x = \frac{- ( - 153 ) + 177}{2 \cdot 11} : 15

x = \frac{- ( - 153 ) - 177}{2 \cdot 11} : - \frac{12}{11}

The solutions to the quadratic equation are:

x = 15, x = - \frac{12}{11}

a^{2} + a + 1 = 0

\frac{c ^{2}}{8} - 3 = 2

x (2 x - 3) = 20

2 = 4 - 8 x^{2} + 4 x^{2} - 5 x - 2 - 3 x + 8 x^{2} - 4 x

x^{2} + (3 a - 2 b) x - 6 ab = 0

What are the solutions to the equation 11x^2-153x-180=0 ?
The solutions to the equation 11x^2-153x-180=0 are x=15,x=-12/11
Find the zeros of 11x^2-153x-180=0
The zeros of 11x^2-153x-180=0 are x=15,x=-12/11