What are the solutions to the equation x(2x-3)=20 ?

The solutions to the equation x(2x-3)=20 are x=4,x=-5/2

Find the zeros of x(2x-3)=20

The zeros of x(2x-3)=20 are x=4,x=-5/2

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x (2 x - 3) = 20

x = 4, x = - \frac{5}{2}

Solution steps

x (2 x - 3) = 20

Expand

x (2 x - 3) : 2 x^{2} - 3 x

2 x^{2} - 3 x = 20

Move

20

to the left side

2 x^{2} - 3 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 20 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 20) = 13

x_{1, 2} = \frac{- ( - 3 ) \pm 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 13}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 13}{2 \cdot 2}

x = \frac{- ( - 3 ) + 13}{2 \cdot 2} : 4

x = \frac{- ( - 3 ) - 13}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 4, x = - \frac{5}{2}

2 = 4 - 8 x^{2} + 4 x^{2} - 5 x - 2 - 3 x + 8 x^{2} - 4 x

x^{2} + (3 a - 2 b) x - 6 ab = 0

120 x - 4.5 x^{2} = 0

5 x^{2} - 7 x = 3

5 x^{2} - 7 x = 6

What are the solutions to the equation x(2x-3)=20 ?
The solutions to the equation x(2x-3)=20 are x=4,x=-5/2
Find the zeros of x(2x-3)=20
The zeros of x(2x-3)=20 are x=4,x=-5/2