What are the solutions to the equation 2=4-8x^2+4x^2-5x-2-3x+8x^2-4x ?

The solutions to the equation 2=4-8x^2+4x^2-5x-2-3x+8x^2-4x are x=3,x=0

Find the zeros of 2=4-8x^2+4x^2-5x-2-3x+8x^2-4x

The zeros of 2=4-8x^2+4x^2-5x-2-3x+8x^2-4x are x=3,x=0

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2 = 4 - 8 x^{2} + 4 x^{2} - 5 x - 2 - 3 x + 8 x^{2} - 4 x

x = 3, x = 0

Solution steps

2 = 4 - 8 x^{2} + 4 x^{2} - 5 x - 2 - 3 x + 8 x^{2} - 4 x

Refine

2 = 4 x^{2} - 12 x + 2

Switch sides

4 x^{2} - 12 x + 2 = 2

Move

2

to the left side

4 x^{2} - 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 0 = 12

x_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 12}{2 \cdot 4}

x = \frac{- ( - 12 ) + 12}{2 \cdot 4} : 3

x = \frac{- ( - 12 ) - 12}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

x^{2} + (3 a - 2 b) x - 6 ab = 0

120 x - 4.5 x^{2} = 0

5 x^{2} - 7 x = 3

5 x^{2} - 7 x = 6

x^{2} - 16 x + 29 = 0

What are the solutions to the equation 2=4-8x^2+4x^2-5x-2-3x+8x^2-4x ?
The solutions to the equation 2=4-8x^2+4x^2-5x-2-3x+8x^2-4x are x=3,x=0
Find the zeros of 2=4-8x^2+4x^2-5x-2-3x+8x^2-4x
The zeros of 2=4-8x^2+4x^2-5x-2-3x+8x^2-4x are x=3,x=0