What are the solutions to the equation x^2-5/6 x= 25/6 ?

The solutions to the equation x^2-5/6 x= 25/6 are x= 5/2 ,x=-5/3

Find the zeros of x^2-5/6 x= 25/6

The zeros of x^2-5/6 x= 25/6 are x= 5/2 ,x=-5/3

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x^{2} - \frac{5}{6} x = \frac{25}{6}

x = \frac{5}{2}, x = - \frac{5}{3}

Decimal Notation

x = 2.5, x = - 1.66666 \dots

Solution steps

x^{2} - \frac{5}{6} x = \frac{25}{6}

Multiply both sides by

6

6 x^{2} - 5 x = 25

Move

25

to the left side

6 x^{2} - 5 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 ( - 25 )}{2 \cdot 6}

(- 5)^{2} - 4 \cdot 6 (- 25) = 25

x_{1, 2} = \frac{- ( - 5 ) \pm 25}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 25}{2 \cdot 6}, x_{2} = \frac{- ( - 5 ) - 25}{2 \cdot 6}

x = \frac{- ( - 5 ) + 25}{2 \cdot 6} : \frac{5}{2}

x = \frac{- ( - 5 ) - 25}{2 \cdot 6} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - \frac{5}{3}

4 x^{2} - 2 x + \frac{1}{4} = 0

(2 x - 1) (3 x + 4) = 0

28 y + 4 = 3 y^{2}

4 x^{2} + 10 x - 13 = 5 x

6 x^{2} + 10 = 4 x

What are the solutions to the equation x^2-5/6 x= 25/6 ?
The solutions to the equation x^2-5/6 x= 25/6 are x= 5/2 ,x=-5/3
Find the zeros of x^2-5/6 x= 25/6
The zeros of x^2-5/6 x= 25/6 are x= 5/2 ,x=-5/3