What are the solutions to the equation X^2-X-6=9 ?

The solutions to the equation X^2-X-6=9 are X=(1+sqrt(61))/2 ,X=(1-sqrt(61))/2

Find the zeros of X^2-X-6=9

The zeros of X^2-X-6=9 are X=(1+sqrt(61))/2 ,X=(1-sqrt(61))/2

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X^{2} - X - 6 = 9

X = \frac{1 + 61}{2}, X = \frac{1 - 61}{2}

Decimal Notation

X = 4.40512 \dots, X = - 3.40512 \dots

Solution steps

X^{2} - X - 6 = 9

Move

9

to the left side

X^{2} - X - 15 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 15) = 61

X_{1, 2} = \frac{- ( - 1 ) \pm 61}{2 \cdot 1}

Separate the solutions

X_{1} = \frac{- ( - 1 ) + 61}{2 \cdot 1}, X_{2} = \frac{- ( - 1 ) - 61}{2 \cdot 1}

X = \frac{- ( - 1 ) + 61}{2 \cdot 1} : \frac{1 + 61}{2}

X = \frac{- ( - 1 ) - 61}{2 \cdot 1} : \frac{1 - 61}{2}

The solutions to the quadratic equation are:

X = \frac{1 + 61}{2}, X = \frac{1 - 61}{2}

x^{2} - \frac{5}{6} x = \frac{25}{6}

4 x^{2} - 2 x + \frac{1}{4} = 0

(2 x - 1) (3 x + 4) = 0

28 y + 4 = 3 y^{2}

4 x^{2} + 10 x - 13 = 5 x

What are the solutions to the equation X^2-X-6=9 ?
The solutions to the equation X^2-X-6=9 are X=(1+sqrt(61))/2 ,X=(1-sqrt(61))/2
Find the zeros of X^2-X-6=9
The zeros of X^2-X-6=9 are X=(1+sqrt(61))/2 ,X=(1-sqrt(61))/2