What are the solutions to the equation 4x^2-2x+1/4 =0 ?

The solutions to the equation 4x^2-2x+1/4 =0 are x= 1/4

Find the zeros of 4x^2-2x+1/4 =0

The zeros of 4x^2-2x+1/4 =0 are x= 1/4

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4 x^{2} - 2 x + \frac{1}{4} = 0

x = \frac{1}{4}

Solution steps

4 x^{2} - 2 x + \frac{1}{4} = 0

Multiply both sides by

4

16 x^{2} - 8 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 16 \cdot 1}{2 \cdot 16}

(- 8)^{2} - 4 \cdot 16 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 8 ) \pm 0}{2 \cdot 16}

x = \frac{- ( - 8 )}{2 \cdot 16}

\frac{- ( - 8 )}{2 \cdot 16} = \frac{1}{4}

x = \frac{1}{4}

The solution to the quadratic equation is:

x = \frac{1}{4}

(2 x - 1) (3 x + 4) = 0

28 y + 4 = 3 y^{2}

4 x^{2} + 10 x - 13 = 5 x

6 x^{2} + 10 = 4 x

2 (x + 1)^{2} - 1 = 9

What are the solutions to the equation 4x^2-2x+1/4 =0 ?
The solutions to the equation 4x^2-2x+1/4 =0 are x= 1/4
Find the zeros of 4x^2-2x+1/4 =0
The zeros of 4x^2-2x+1/4 =0 are x= 1/4