What are the solutions to the equation x^2-8x+16=36 ?

The solutions to the equation x^2-8x+16=36 are x=10,x=-2

Find the zeros of x^2-8x+16=36

The zeros of x^2-8x+16=36 are x=10,x=-2

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x^{2} - 8 x + 16 = 36

x = 10, x = - 2

Solution steps

x^{2} - 8 x + 16 = 36

Move

36

to the left side

x^{2} - 8 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 20) = 12

x_{1, 2} = \frac{- ( - 8 ) \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 12}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 12}{2 \cdot 1}

x = \frac{- ( - 8 ) + 12}{2 \cdot 1} : 10

x = \frac{- ( - 8 ) - 12}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 10, x = - 2

4^{2} + b^{2} = 7^{2}

1 0^{2} + y^{2} = 1 2^{2}

p^{2} + 8 p + 15 = 0

3 x^{2} - 8 x + 12 = 0

x^{2} = 6^{2} + 2^{2}

What are the solutions to the equation x^2-8x+16=36 ?
The solutions to the equation x^2-8x+16=36 are x=10,x=-2
Find the zeros of x^2-8x+16=36
The zeros of x^2-8x+16=36 are x=10,x=-2