What are the solutions to the equation 4^2+b^2=7^2 ?

The solutions to the equation 4^2+b^2=7^2 are b=sqrt(33),b=-sqrt(33)

Find the zeros of 4^2+b^2=7^2

The zeros of 4^2+b^2=7^2 are b=sqrt(33),b=-sqrt(33)

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4^{2} + b^{2} = 7^{2}

b = 33, b = - 33

Decimal Notation

b = 5.74456 \dots, b = - 5.74456 \dots

Solution steps

4^{2} + b^{2} = 7^{2}

Move

4^{2}

to the right side

b^{2} = 33

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 33, b = - 33

1 0^{2} + y^{2} = 1 2^{2}

p^{2} + 8 p + 15 = 0

3 x^{2} - 8 x + 12 = 0

x^{2} = 6^{2} + 2^{2}

3 (x - 4)^{2} = 2 (x - 4)

What are the solutions to the equation 4^2+b^2=7^2 ?
The solutions to the equation 4^2+b^2=7^2 are b=sqrt(33),b=-sqrt(33)
Find the zeros of 4^2+b^2=7^2
The zeros of 4^2+b^2=7^2 are b=sqrt(33),b=-sqrt(33)