What are the solutions to the equation -x=2x-x^2 ?

The solutions to the equation -x=2x-x^2 are x=0,x=3

Find the zeros of -x=2x-x^2

The zeros of -x=2x-x^2 are x=0,x=3

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- x = 2 x - x^{2}

x = 0, x = 3

Solution steps

- x = 2 x - x^{2}

Switch sides

2 x - x^{2} = - x

Move

x

to the left side

- x^{2} + 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 0 = 3

x_{1, 2} = \frac{- 3 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 3}{2 ( - 1 )}, x_{2} = \frac{- 3 - 3}{2 ( - 1 )}

x = \frac{- 3 + 3}{2 ( - 1 )} : 0

x = \frac{- 3 - 3}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = 0, x = 3

- 3 x^{2} - x + 2 = 0

x^{2} + 29 x + 100 = 0

x, x^{2} - 7 x + 12 = 0

36 - 25 x^{2} = 0

x (x + 2) = 143

What are the solutions to the equation -x=2x-x^2 ?
The solutions to the equation -x=2x-x^2 are x=0,x=3
Find the zeros of -x=2x-x^2
The zeros of -x=2x-x^2 are x=0,x=3