What are the solutions to the equation 20x^2=-3x ?

The solutions to the equation 20x^2=-3x are x=0,x=-3/20

Find the zeros of 20x^2=-3x

The zeros of 20x^2=-3x are x=0,x=-3/20

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20 x^{2} = - 3 x

x = 0, x = - \frac{3}{20}

Decimal Notation

x = 0, x = - 0.15

Solution steps

20 x^{2} = - 3 x

Move

3 x

to the left side

20 x^{2} + 3 x = 0

Factor

20 x^{2} + 3 x : x (20 x + 3)

x (20 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 20 x + 3 = 0

Solve

20 x + 3 = 0 : x = - \frac{3}{20}

The solutions to the quadratic equation are:

x = 0, x = - \frac{3}{20}

x, x^{2} + y^{2} + z^{2} + 8 x - 6 y - 4 z - 7 = 0

4 x^{2} + 9 - 12 x = 0

\frac{8}{3} = 4 - x^{2}

(x - 2) 2 + x (x + 1) = 24

x^{2} + 8 x - 32 = 0

What are the solutions to the equation 20x^2=-3x ?
The solutions to the equation 20x^2=-3x are x=0,x=-3/20
Find the zeros of 20x^2=-3x
The zeros of 20x^2=-3x are x=0,x=-3/20