What are the solutions to the equation 4x^2+9-12x=0 ?

The solutions to the equation 4x^2+9-12x=0 are x= 3/2

Find the zeros of 4x^2+9-12x=0

The zeros of 4x^2+9-12x=0 are x= 3/2

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4 x^{2} + 9 - 12 x = 0

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

4 x^{2} + 9 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 12 )}{2 \cdot 4}

\frac{- ( - 12 )}{2 \cdot 4} = \frac{3}{2}

x = \frac{3}{2}

The solution to the quadratic equation is:

x = \frac{3}{2}

\frac{8}{3} = 4 - x^{2}

(x - 2) 2 + x (x + 1) = 24

x^{2} + 8 x - 32 = 0

z, x^{3} z^{2} - 5 x y^{5} z = x^{2} + y^{3}

5 x^{2} - x + 6 = 5 - 7 x - 4 x^{2}

What are the solutions to the equation 4x^2+9-12x=0 ?
The solutions to the equation 4x^2+9-12x=0 are x= 3/2
Find the zeros of 4x^2+9-12x=0
The zeros of 4x^2+9-12x=0 are x= 3/2