What are the solutions to the equation quadraticformula x^2+2x-5=0 ?

The solutions to the equation quadraticformula x^2+2x-5=0 are x=-1+sqrt(6),x=-1-sqrt(6)

Find the zeros of quadraticformula x^2+2x-5=0

The zeros of quadraticformula x^2+2x-5=0 are x=-1+sqrt(6),x=-1-sqrt(6)

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x^{2} + 2 x - 5 = 0

x = - 1 + 6, x = - 1 - 6

Decimal Notation

x = 1.44948 \dots, x = - 3.44948 \dots

Solution steps

x^{2} + 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 5) = 26

x_{1, 2} = \frac{- 2 \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 6}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 6}{2 \cdot 1}

x = \frac{- 2 + 2 6}{2 \cdot 1} : - 1 + 6

x = \frac{- 2 - 2 6}{2 \cdot 1} : - 1 - 6

The solutions to the quadratic equation are:

x = - 1 + 6, x = - 1 - 6

0 = (x - 3)^{2} + 1

x, z = 4 - x^{2} - 2 y^{2}

x, x^{2} + m x + 7 = 0

5 b^{2} + 4 b + 4 = 0

\frac{1}{16} x^{2} + x + 4 = 0

What are the solutions to the equation quadraticformula x^2+2x-5=0 ?
The solutions to the equation quadraticformula x^2+2x-5=0 are x=-1+sqrt(6),x=-1-sqrt(6)
Find the zeros of quadraticformula x^2+2x-5=0
The zeros of quadraticformula x^2+2x-5=0 are x=-1+sqrt(6),x=-1-sqrt(6)