What are the solutions to the equation a^2+2a-5=0 ?

The solutions to the equation a^2+2a-5=0 are a=-1+sqrt(6),a=-1-sqrt(6)

Find the zeros of a^2+2a-5=0

The zeros of a^2+2a-5=0 are a=-1+sqrt(6),a=-1-sqrt(6)

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a^{2} + 2 a - 5 = 0

a = - 1 + 6, a = - 1 - 6

Solution steps

a^{2} + 2 a - 5 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 5) = 26

a_{1, 2} = \frac{- 2 \pm 2 6}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 2 + 2 6}{2 \cdot 1}, a_{2} = \frac{- 2 - 2 6}{2 \cdot 1}

a = \frac{- 2 + 2 6}{2 \cdot 1} : - 1 + 6

a = \frac{- 2 - 2 6}{2 \cdot 1} : - 1 - 6

The solutions to the quadratic equation are:

a = - 1 + 6, a = - 1 - 6

3 x = \frac{1}{5} x^{2} + 10

x^{2} - 18 x - 360 = 0

w, x yz + x z w - yz w + w^{2} = 5

4 x^{2} + 12 x - 3 = 0

(b + 7)^{2} = 8

What are the solutions to the equation a^2+2a-5=0 ?
The solutions to the equation a^2+2a-5=0 are a=-1+sqrt(6),a=-1-sqrt(6)
Find the zeros of a^2+2a-5=0
The zeros of a^2+2a-5=0 are a=-1+sqrt(6),a=-1-sqrt(6)