What are the solutions to the equation 64x^2+144x+81=0 ?

The solutions to the equation 64x^2+144x+81=0 are x=-9/8

Find the zeros of 64x^2+144x+81=0

The zeros of 64x^2+144x+81=0 are x=-9/8

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64 x^{2} + 144 x + 81 = 0

x = - \frac{9}{8}

Solution steps

64 x^{2} + 144 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 144 \pm 14 4 ^{2} - 4 \cdot 64 \cdot 81}{2 \cdot 64}

14 4^{2} - 4 \cdot 64 \cdot 81 = 0

x_{1, 2} = \frac{- 144 \pm 0}{2 \cdot 64}

x = \frac{- 144}{2 \cdot 64}

\frac{- 144}{2 \cdot 64} = - \frac{9}{8}

x = - \frac{9}{8}

The solution to the quadratic equation is:

x = - \frac{9}{8}

A = x^{2} + 4 x + 11

x, y = x^{2} - 6 x + 9

x, y = x^{2} - 6 x + 5

3 x^{2} + 4 = - 6 x

7 (x - 9)^{2} = x (x - 3)

What are the solutions to the equation 64x^2+144x+81=0 ?
The solutions to the equation 64x^2+144x+81=0 are x=-9/8
Find the zeros of 64x^2+144x+81=0
The zeros of 64x^2+144x+81=0 are x=-9/8