What are the solutions to the equation 7(x-9)^2=x(x-3) ?

The solutions to the equation 7(x-9)^2=x(x-3) are x= 27/2 ,x=7

Find the zeros of 7(x-9)^2=x(x-3)

The zeros of 7(x-9)^2=x(x-3) are x= 27/2 ,x=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 (x - 9)^{2} = x (x - 3)

x = \frac{27}{2}, x = 7

Solution steps

7 (x - 9)^{2} = x (x - 3)

Expand

7 (x - 9)^{2} : 7 x^{2} - 126 x + 567

Expand

x (x - 3) : x^{2} - 3 x

7 x^{2} - 126 x + 567 = x^{2} - 3 x

Move

3 x

to the left side

7 x^{2} - 123 x + 567 = x^{2}

Move

x^{2}

to the left side

6 x^{2} - 123 x + 567 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 123 ) \pm ( - 123 ) ^{2} - 4 \cdot 6 \cdot 567}{2 \cdot 6}

(- 123)^{2} - 4 \cdot 6 \cdot 567 = 39

x_{1, 2} = \frac{- ( - 123 ) \pm 39}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 123 ) + 39}{2 \cdot 6}, x_{2} = \frac{- ( - 123 ) - 39}{2 \cdot 6}

x = \frac{- ( - 123 ) + 39}{2 \cdot 6} : \frac{27}{2}

x = \frac{- ( - 123 ) - 39}{2 \cdot 6} : 7

The solutions to the quadratic equation are:

x = \frac{27}{2}, x = 7

- 4 x^{2} + 12 x - a = 0

4 q^{2} + 4 q + 1 = 0

x^{2} - 10 x + 25 = 0

x, 9 x^{2} - 18 x y + 9 y^{2} - x - y = 0

12 x^{2} - 88 x + 96 = 0

What are the solutions to the equation 7(x-9)^2=x(x-3) ?
The solutions to the equation 7(x-9)^2=x(x-3) are x= 27/2 ,x=7
Find the zeros of 7(x-9)^2=x(x-3)
The zeros of 7(x-9)^2=x(x-3) are x= 27/2 ,x=7