What are the solutions to the equation 3x^2+4=-6x ?

The solutions to the equation 3x^2+4=-6x are x=-1+i(sqrt(3))/3 ,x=-1-i(sqrt(3))/3

Find the zeros of 3x^2+4=-6x

The zeros of 3x^2+4=-6x are x=-1+i(sqrt(3))/3 ,x=-1-i(sqrt(3))/3

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3 x^{2} + 4 = - 6 x

x = - 1 + i \frac{3}{3}, x = - 1 - i \frac{3}{3}

Solution steps

3 x^{2} + 4 = - 6 x

Move

6 x

to the left side

3 x^{2} + 4 + 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 6 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

Simplify

6^{2} - 4 \cdot 3 \cdot 4 : 23 i

x_{1, 2} = \frac{- 6 \pm 2 3 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 2 3 i}{2 \cdot 3}, x_{2} = \frac{- 6 - 2 3 i}{2 \cdot 3}

x = \frac{- 6 + 2 3 i}{2 \cdot 3} : - 1 + i \frac{3}{3}

x = \frac{- 6 - 2 3 i}{2 \cdot 3} : - 1 - i \frac{3}{3}

The solutions to the quadratic equation are:

x = - 1 + i \frac{3}{3}, x = - 1 - i \frac{3}{3}

7 (x - 9)^{2} = x (x - 3)

- 4 x^{2} + 12 x - a = 0

4 q^{2} + 4 q + 1 = 0

x^{2} - 10 x + 25 = 0

x, 9 x^{2} - 18 x y + 9 y^{2} - x - y = 0

What are the solutions to the equation 3x^2+4=-6x ?
The solutions to the equation 3x^2+4=-6x are x=-1+i(sqrt(3))/3 ,x=-1-i(sqrt(3))/3
Find the zeros of 3x^2+4=-6x
The zeros of 3x^2+4=-6x are x=-1+i(sqrt(3))/3 ,x=-1-i(sqrt(3))/3