What are the solutions to the equation solvefor x,y=x^2-6x+5 ?

The solutions to the equation solvefor x,y=x^2-6x+5 are x=3+sqrt(y+4),x=3-sqrt(y+4)

Find the zeros of solvefor x,y=x^2-6x+5

The zeros of solvefor x,y=x^2-6x+5 are x=3+sqrt(y+4),x=3-sqrt(y+4)

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solve for

x, y = x^{2} - 6 x + 5

x = 3 + y + 4, x = 3 - y + 4

Solution steps

y = x^{2} - 6 x + 5

Switch sides

x^{2} - 6 x + 5 = y

Move

y

to the left side

x^{2} - 6 x + 5 - y = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( 5 - y )}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot (5 - y) : 2 y + 4

x_{1, 2} = \frac{- ( - 6 ) \pm 2 y + 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 y + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 y + 4}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 y + 4}{2 \cdot 1} : 3 + y + 4

x = \frac{- ( - 6 ) - 2 y + 4}{2 \cdot 1} : 3 - y + 4

The solutions to the quadratic equation are:

x = 3 + y + 4, x = 3 - y + 4

3 x^{2} + 4 = - 6 x

7 (x - 9)^{2} = x (x - 3)

- 4 x^{2} + 12 x - a = 0

4 q^{2} + 4 q + 1 = 0

x^{2} - 10 x + 25 = 0

What are the solutions to the equation solvefor x,y=x^2-6x+5 ?
The solutions to the equation solvefor x,y=x^2-6x+5 are x=3+sqrt(y+4),x=3-sqrt(y+4)
Find the zeros of solvefor x,y=x^2-6x+5
The zeros of solvefor x,y=x^2-6x+5 are x=3+sqrt(y+4),x=3-sqrt(y+4)