What are the solutions to the equation A=x^2+4x+11 ?

The solutions to the equation A=x^2+4x+11 are x=-2+sqrt(A-7),x=-sqrt(A-7)-2

Find the zeros of A=x^2+4x+11

The zeros of A=x^2+4x+11 are x=-2+sqrt(A-7),x=-sqrt(A-7)-2

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A = x^{2} + 4 x + 11

x = - 2 + A - 7, x = - A - 7 - 2

Solution steps

A = x^{2} + 4 x + 11

Switch sides

x^{2} + 4 x + 11 = A

Move

A

to the left side

x^{2} + 4 x + 11 - A = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( 11 - A )}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot (11 - A) : 2 A - 7

x_{1, 2} = \frac{- 4 \pm 2 A - 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 A - 7}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 A - 7}{2 \cdot 1}

x = \frac{- 4 + 2 A - 7}{2 \cdot 1} : - 2 + A - 7

x = \frac{- 4 - 2 A - 7}{2 \cdot 1} : - A - 7 - 2

The solutions to the quadratic equation are:

x = - 2 + A - 7, x = - A - 7 - 2

x, y = x^{2} - 6 x + 9

x, y = x^{2} - 6 x + 5

3 x^{2} + 4 = - 6 x

7 (x - 9)^{2} = x (x - 3)

- 4 x^{2} + 12 x - a = 0

What are the solutions to the equation A=x^2+4x+11 ?
The solutions to the equation A=x^2+4x+11 are x=-2+sqrt(A-7),x=-sqrt(A-7)-2
Find the zeros of A=x^2+4x+11
The zeros of A=x^2+4x+11 are x=-2+sqrt(A-7),x=-sqrt(A-7)-2