What is expand-1(-x/5+y-2+1/5 =0) ?

The solution to expand-1(-x/5+y-2+1/5 =0) is x/5-1/5-y+2=0

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expand-1(-x/5+y-2+1/5 =0)

expand

- 1 (- \frac{x}{5} + y - 2 + \frac{1}{5} = 0)

\frac{x}{5} - \frac{1}{5} - y + 2 = 0

Solution steps

- 1 \cdot (- \frac{x}{5} + y - 2 + \frac{1}{5} = 0)

= - 1 \cdot (- \frac{x}{5} + y - 2 + 0 \cdot \frac{1}{5} =)

Distribute parentheses

(- 1) (- \frac{x}{5}) + (- 1) y + (- 1) (- 2) + (- 1) \frac{1}{5} = 0

Apply minus-plus rules

(- a) (- b) = ab, + (- a) = - a

1 \cdot \frac{x}{5} - 1 \cdot y + 1 \cdot 2 - 1 \cdot \frac{1}{5} = 0

Expand

1 \cdot \frac{x}{5} - 1 \cdot y + 1 \cdot 2 - 1 \cdot \frac{1}{5} : \frac{x}{5} - \frac{1}{5} - y + 2

\frac{x}{5} - \frac{1}{5} - y + 2 = 0

(u^{2}, v^{2}, u^{2} + v^{2} + 2 uv - 8 u - 8 v + 16) \cdot (1, - 1, 1)

\frac{( x ^{3} - 5 x + 4 )}{x - 1}

\frac{d ( d - 1 ) ( d - 2 )}{6}

\frac{1}{( s + 1 ) ( s + 3 ) ( s + 5 )}

\frac{7 x}{( 2 x + 1 ) ( x - 3 )}

What is expand-1(-x/5+y-2+1/5 =0) ?
The solution to expand-1(-x/5+y-2+1/5 =0) is x/5-1/5-y+2=0