What is expand (u^2,v^2,u^2+v^2+2uv-8u-8v+16)*(1,-1,1) ?

The solution to expand (u^2,v^2,u^2+v^2+2uv-8u-8v+16)*(1,-1,1) is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (u^2,v^2,u^2+v^2+2uv-8u-8v+16)*(1,-1,1)

expand

(u^{2}, v^{2}, u^{2} + v^{2} + 2 uv - 8 u - 8 v + 16) \cdot (1, - 1, 1)

u^{2}, v^{2}, 1 \cdot u^{2}, - u^{2}, v^{2}, 1 \cdot u^{2}, 1 + 1 \cdot v^{2}, - 1 \cdot v^{2}, 1 + 2 \cdot 1 \cdot uv, - 2 \cdot 1 \cdot uv, 1 - 8 \cdot 1 \cdot u, 8 \cdot 1 \cdot u, 1 - 8 \cdot 1 \cdot v, 8 \cdot 1 \cdot v, 1 + 16 \cdot 1, - 16 \cdot 1, 1

Solution steps

(u^{2}, v^{2}, u^{2} + v^{2} + 2 uv - 8 u - 8 v + 16) (1, - 1, 1)

= (1, - 1 \cdot 1,) (,, u^{2} u^{2} v^{2} + v^{2} + 2 uv - 8 u - 8 v + 16)

Distribute parentheses

= u^{2}, v^{2}, u^{2} \cdot 1, u^{2}, v^{2}, u^{2} (- 1, 1) + v^{2} \cdot 1, v^{2} (- 1, 1) + 2 uv \cdot 1, 2 uv (- 1, 1) + (- 8 u) \cdot 1, (- 8 u) (- 1, 1) + (- 8 v) \cdot 1, (- 8 v) (- 1, 1) + 16 \cdot 1, 16 (- 1, 1)

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= u^{2}, v^{2}, 1 \cdot u^{2}, - u^{2}, v^{2}, 1 \cdot u^{2}, 1 + 1 \cdot v^{2}, - 1 \cdot v^{2}, 1 + 2 \cdot 1 \cdot uv, - 2 \cdot 1 \cdot uv, 1 - 8 \cdot 1 \cdot u, 8 \cdot 1 \cdot u, 1 - 8 \cdot 1 \cdot v, 8 \cdot 1 \cdot v, 1 + 16 \cdot 1, - 16 \cdot 1, 1

\frac{( x ^{3} - 5 x + 4 )}{x - 1}

\frac{d ( d - 1 ) ( d - 2 )}{6}

\frac{1}{( s + 1 ) ( s + 3 ) ( s + 5 )}

\frac{7 x}{( 2 x + 1 ) ( x - 3 )}

\frac{2 ( 3 e ^{3 π} + 1 ) ( 3 e ^{3 π} - 1 )}{e ^{6 π}}

What is expand (u^2,v^2,u^2+v^2+2uv-8u-8v+16)*(1,-1,1) ?
The solution to expand (u^2,v^2,u^2+v^2+2uv-8u-8v+16)*(1,-1,1) is