What are the solutions to the equation 0=t^2-6t+5 ?

The solutions to the equation 0=t^2-6t+5 are t=5,t=1

Find the zeros of 0=t^2-6t+5

The zeros of 0=t^2-6t+5 are t=5,t=1

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0 = t^{2} - 6 t + 5

t = 5, t = 1

Solution steps

0 = t^{2} - 6 t + 5

Switch sides

t^{2} - 6 t + 5 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 5 = 4

t_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 1}, t_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 1}

t = \frac{- ( - 6 ) + 4}{2 \cdot 1} : 5

t = \frac{- ( - 6 ) - 4}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

t = 5, t = 1

3 x^{2} + 2 x - 1 = 0

a, 70 a^{2} - 149 ab + 70 b^{2} = 0

8 x^{2} - 55 x + 42 = 0

t^{2} + 2 t + 3 = 0

3 y^{2} - 17 y + 10 = 0

What are the solutions to the equation 0=t^2-6t+5 ?
The solutions to the equation 0=t^2-6t+5 are t=5,t=1
Find the zeros of 0=t^2-6t+5
The zeros of 0=t^2-6t+5 are t=5,t=1