What are the solutions to the equation 240-600x+30x^2=0 ?

The solutions to the equation 240-600x+30x^2=0 are x=2(5+sqrt(23)),x=2(5-sqrt(23))

Find the zeros of 240-600x+30x^2=0

The zeros of 240-600x+30x^2=0 are x=2(5+sqrt(23)),x=2(5-sqrt(23))

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240 - 600 x + 30 x^{2} = 0

x = 2 (5 + 23), x = 2 (5 - 23)

Decimal Notation

x = 19.59166 \dots, x = 0.40833 \dots

Solution steps

240 - 600 x + 30 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

30 x^{2} - 600 x + 240 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 600 ) \pm ( - 600 ) ^{2} - 4 \cdot 30 \cdot 240}{2 \cdot 30}

(- 600)^{2} - 4 \cdot 30 \cdot 240 = 12023

x_{1, 2} = \frac{- ( - 600 ) \pm 120 23}{2 \cdot 30}

Separate the solutions

x_{1} = \frac{- ( - 600 ) + 120 23}{2 \cdot 30}, x_{2} = \frac{- ( - 600 ) - 120 23}{2 \cdot 30}

x = \frac{- ( - 600 ) + 120 23}{2 \cdot 30} : 2 (5 + 23)

x = \frac{- ( - 600 ) - 120 23}{2 \cdot 30} : 2 (5 - 23)

The solutions to the quadratic equation are:

x = 2 (5 + 23), x = 2 (5 - 23)

4 x^{2} + 16 x - 84 = 0

a, a^{2} - ab + b^{2} = 0

s^{2} + s + 2 + k = 0

\frac{5}{16} x^{2} - x - 1 = 0

6 a^{2} - 9 a + 15 = 0

What are the solutions to the equation 240-600x+30x^2=0 ?
The solutions to the equation 240-600x+30x^2=0 are x=2(5+sqrt(23)),x=2(5-sqrt(23))
Find the zeros of 240-600x+30x^2=0
The zeros of 240-600x+30x^2=0 are x=2(5+sqrt(23)),x=2(5-sqrt(23))