What are the solutions to the equation 4x^2+16x-84=0 ?

The solutions to the equation 4x^2+16x-84=0 are x=3,x=-7

Find the zeros of 4x^2+16x-84=0

The zeros of 4x^2+16x-84=0 are x=3,x=-7

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4 x^{2} + 16 x - 84 = 0

x = 3, x = - 7

Solution steps

4 x^{2} + 16 x - 84 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 4 ( - 84 )}{2 \cdot 4}

1 6^{2} - 4 \cdot 4 (- 84) = 40

x_{1, 2} = \frac{- 16 \pm 40}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 16 + 40}{2 \cdot 4}, x_{2} = \frac{- 16 - 40}{2 \cdot 4}

x = \frac{- 16 + 40}{2 \cdot 4} : 3

x = \frac{- 16 - 40}{2 \cdot 4} : - 7

The solutions to the quadratic equation are:

x = 3, x = - 7

a, a^{2} - ab + b^{2} = 0

s^{2} + s + 2 + k = 0

\frac{5}{16} x^{2} - x - 1 = 0

6 a^{2} - 9 a + 15 = 0

x^{2} + 2 x = 9 x - 6

What are the solutions to the equation 4x^2+16x-84=0 ?
The solutions to the equation 4x^2+16x-84=0 are x=3,x=-7
Find the zeros of 4x^2+16x-84=0
The zeros of 4x^2+16x-84=0 are x=3,x=-7