What are the solutions to the equation 9a^2-6a+1=0 ?

The solutions to the equation 9a^2-6a+1=0 are a= 1/3

Find the zeros of 9a^2-6a+1=0

The zeros of 9a^2-6a+1=0 are a= 1/3

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9 a^{2} - 6 a + 1 = 0

a = \frac{1}{3}

Decimal Notation

a = 0.33333 \dots

Solution steps

9 a^{2} - 6 a + 1 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

(- 6)^{2} - 4 \cdot 9 \cdot 1 = 0

a_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 9}

a = \frac{- ( - 6 )}{2 \cdot 9}

\frac{- ( - 6 )}{2 \cdot 9} = \frac{1}{3}

a = \frac{1}{3}

The solution to the quadratic equation is:

a = \frac{1}{3}

a, a^{2} + b^{2} = \frac{5}{2} ab

5 x^{2} + 20 x = 18 x + 720 + 2 x

x, y = x^{2} - 1

x, y = x^{2} - 2

x (x + 7) = 690

What are the solutions to the equation 9a^2-6a+1=0 ?
The solutions to the equation 9a^2-6a+1=0 are a= 1/3
Find the zeros of 9a^2-6a+1=0
The zeros of 9a^2-6a+1=0 are a= 1/3