What is the answer to 2^x+3*2^x=16 ?

The answer to 2^x+3*2^x=16 is x=2

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2^x+3*2^x=16

2^{x} + 3 \cdot 2^{x} = 16

x = 2

Solution steps

2^{x} + 3 \cdot 2^{x} = 16

Add similar elements:

2^{x} + 3 \cdot 2^{x} = 4 \cdot 2^{x}

4 \cdot 2^{x} = 16

Divide both sides by

4

2^{x} = 4

Apply exponent rules

x = 2

x, \frac{( 9 ^{x - 1} )}{( 3 ^{y + 2} )} = 81

1 6^{x} + 2 0^{x} + 2 5^{x} = 0

3 2^{x} = 8

(\frac{1}{9})^{6 x + 1} = 9^{7 - x}

x, y^{x} - y^{y} = - 26