What is f(x)=2,x^2+11x-219x= 3/2 ?

The solution to f(x)=2,x^2+11x-219x= 3/2 is

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f(x)=2,x^2+11x-219x= 3/2

f (x) = 2, x^{2} + 11 x - 219 x = \frac{3}{2}

(x = \frac{208 + 43270}{2}, x = \frac{208 - 43270}{2}, f = 2 f = 2)

Solution steps

[f = 2 x^{2} + 11 x - 219 x = \frac{3}{2}]

Solve

x^{2} + 11 x - 219 x = \frac{3}{2} : x = \frac{208 + 43270}{2}, x = \frac{208 - 43270}{2}

Plug the solutions

x = \frac{208 + 43270}{2}, x = \frac{208 - 43270}{2}

into

f = 2

For

f = 2

, subsitute

x

with

\frac{208 + 43270}{2} : f = 2

For

f = 2

, subsitute

x

with

\frac{208 - 43270}{2} : f = 2

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

f = 2, x^{2} + 11 x - 219 x = \frac{3}{2}

are

(x = \frac{208 + 43270}{2}, x = \frac{208 - 43270}{2}, f = 2 f = 2)

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