What are the solutions to the equation (2x+3)(3x-7)=0 ?

The solutions to the equation (2x+3)(3x-7)=0 are x=-3/2 ,x= 7/3

Find the zeros of (2x+3)(3x-7)=0

The zeros of (2x+3)(3x-7)=0 are x=-3/2 ,x= 7/3

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(2 x + 3) (3 x - 7) = 0

x = - \frac{3}{2}, x = \frac{7}{3}

Decimal Notation

x = - 1.5, x = 2.33333 \dots

Solution steps

(2 x + 3) (3 x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 3 = 0 or 3 x - 7 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

3 x - 7 = 0 : x = \frac{7}{3}

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = \frac{7}{3}

3 (x + 4)^{2} = 8

- 4 + 16 x - 15 x^{2} = 0

4 x^{2} - 20 x + 29 = 0

(x + 5)^{2} + 5 (2 x + 3) = 2 (x + 4)^{2}

4 x^{2} + 40 x + 100 = 0

What are the solutions to the equation (2x+3)(3x-7)=0 ?
The solutions to the equation (2x+3)(3x-7)=0 are x=-3/2 ,x= 7/3
Find the zeros of (2x+3)(3x-7)=0
The zeros of (2x+3)(3x-7)=0 are x=-3/2 ,x= 7/3