What are the solutions to the equation 9x^2+18x-68=7 ?

The solutions to the equation 9x^2+18x-68=7 are x=(-3+2sqrt(21))/3 ,x=-(3+2sqrt(21))/3

Find the zeros of 9x^2+18x-68=7

The zeros of 9x^2+18x-68=7 are x=(-3+2sqrt(21))/3 ,x=-(3+2sqrt(21))/3

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9 x^{2} + 18 x - 68 = 7

x = \frac{- 3 + 2 21}{3}, x = - \frac{3 + 2 21}{3}

Solution steps

9 x^{2} + 18 x - 68 = 7

Move

7

to the left side

9 x^{2} + 18 x - 75 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 9 ( - 75 )}{2 \cdot 9}

1 8^{2} - 4 \cdot 9 (- 75) = 1221

x_{1, 2} = \frac{- 18 \pm 12 21}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 18 + 12 21}{2 \cdot 9}, x_{2} = \frac{- 18 - 12 21}{2 \cdot 9}

x = \frac{- 18 + 12 21}{2 \cdot 9} : \frac{- 3 + 2 21}{3}

x = \frac{- 18 - 12 21}{2 \cdot 9} : - \frac{3 + 2 21}{3}

The solutions to the quadratic equation are:

x = \frac{- 3 + 2 21}{3}, x = - \frac{3 + 2 21}{3}

3 x^{2} - 2 x + 4 = 0

(5 m + 1)^{2} = 7

2 x^{2} + 4 x + 2 = 0

49 x^{2} + 9 = 42 x

z^{2} + 11 z + 16 = 0

What are the solutions to the equation 9x^2+18x-68=7 ?
The solutions to the equation 9x^2+18x-68=7 are x=(-3+2sqrt(21))/3 ,x=-(3+2sqrt(21))/3
Find the zeros of 9x^2+18x-68=7
The zeros of 9x^2+18x-68=7 are x=(-3+2sqrt(21))/3 ,x=-(3+2sqrt(21))/3