What are the solutions to the equation 4x^2+2x=13 ?

The solutions to the equation 4x^2+2x=13 are x=(-1+sqrt(53))/4 ,x=-(1+sqrt(53))/4

Find the zeros of 4x^2+2x=13

The zeros of 4x^2+2x=13 are x=(-1+sqrt(53))/4 ,x=-(1+sqrt(53))/4

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4 x^{2} + 2 x = 13

x = \frac{- 1 + 53}{4}, x = - \frac{1 + 53}{4}

Decimal Notation

x = 1.57002 \dots, x = - 2.07002 \dots

Solution steps

4 x^{2} + 2 x = 13

Move

13

to the left side

4 x^{2} + 2 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 4 ( - 13 )}{2 \cdot 4}

2^{2} - 4 \cdot 4 (- 13) = 253

x_{1, 2} = \frac{- 2 \pm 2 53}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 2 + 2 53}{2 \cdot 4}, x_{2} = \frac{- 2 - 2 53}{2 \cdot 4}

x = \frac{- 2 + 2 53}{2 \cdot 4} : \frac{- 1 + 53}{4}

x = \frac{- 2 - 2 53}{2 \cdot 4} : - \frac{1 + 53}{4}

The solutions to the quadratic equation are:

x = \frac{- 1 + 53}{4}, x = - \frac{1 + 53}{4}

11 x^{2} - 4 x + 11 = 0

X^{2} - 7 X - 18 = 0

x (1 - x) + (- 0.02) - 0.1 x = 0

3 x^{2} + (0 + 1) x - 2 = 0

2 z^{2} - 11 = - 4

What are the solutions to the equation 4x^2+2x=13 ?
The solutions to the equation 4x^2+2x=13 are x=(-1+sqrt(53))/4 ,x=-(1+sqrt(53))/4
Find the zeros of 4x^2+2x=13
The zeros of 4x^2+2x=13 are x=(-1+sqrt(53))/4 ,x=-(1+sqrt(53))/4