What are the solutions to the equation completesquare 9x^2-6x+1=0 ?

The solutions to the equation completesquare 9x^2-6x+1=0 are x= 1/3

Find the zeros of completesquare 9x^2-6x+1=0

The zeros of completesquare 9x^2-6x+1=0 are x= 1/3

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9 x^{2} - 6 x + 1 = 0

x = \frac{1}{3}

Decimal Notation

x = 0.33333 \dots

Solution steps

9 x^{2} - 6 x + 1 = 0

Move

1

to the right side

9 x^{2} - 6 x = - 1

Divide both sides by

9

\frac{9 x ^{2} - 6 x}{9} = \frac{- 1}{9}

x^{2} - \frac{2 x}{3} = - \frac{1}{9}

Rewrite in the form

(x + a)^{2} = b

(x - \frac{1}{3})^{2} = 0

Solve

x - \frac{1}{3} = 0 : x = \frac{1}{3}

The solution to the quadratic equation is:

x = \frac{1}{3}

(x - 2)^{2} - 5 = 0

(2 w + 1) w = 66

a, x = a^{2} + b^{2} + c^{3}

x^{2} - 3 x = 7 x^{2} + 5 x

2 x (x - 5) = - 3 x - 3

What are the solutions to the equation completesquare 9x^2-6x+1=0 ?
The solutions to the equation completesquare 9x^2-6x+1=0 are x= 1/3
Find the zeros of completesquare 9x^2-6x+1=0
The zeros of completesquare 9x^2-6x+1=0 are x= 1/3