What are the solutions to the equation -12x=3-5x^2 ?

The solutions to the equation -12x=3-5x^2 are x=-(-6+sqrt(51))/5 ,x=(6+sqrt(51))/5

Find the zeros of -12x=3-5x^2

The zeros of -12x=3-5x^2 are x=-(-6+sqrt(51))/5 ,x=(6+sqrt(51))/5

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- 12 x = 3 - 5 x^{2}

x = - \frac{- 6 + 51}{5}, x = \frac{6 + 51}{5}

Solution steps

- 12 x = 3 - 5 x^{2}

Switch sides

3 - 5 x^{2} = - 12 x

Move

12 x

to the left side

3 - 5 x^{2} + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 5 x^{2} + 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 5 ) \cdot 3}{2 ( - 5 )}

1 2^{2} - 4 (- 5) \cdot 3 = 251

x_{1, 2} = \frac{- 12 \pm 2 51}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 12 + 2 51}{2 ( - 5 )}, x_{2} = \frac{- 12 - 2 51}{2 ( - 5 )}

x = \frac{- 12 + 2 51}{2 ( - 5 )} : - \frac{- 6 + 51}{5}

x = \frac{- 12 - 2 51}{2 ( - 5 )} : \frac{6 + 51}{5}

The solutions to the quadratic equation are:

x = - \frac{- 6 + 51}{5}, x = \frac{6 + 51}{5}

4 k^{2} + 41 k + 10 = 0

x^{2} - 6 x + 5 = - 4

3 k^{2} - 4 k - 4 = k

(3 x + 9)^{2} = 81

k (x) = 2 x^{2} + 3 x - 1, f (x, h) (a + h)

What are the solutions to the equation -12x=3-5x^2 ?
The solutions to the equation -12x=3-5x^2 are x=-(-6+sqrt(51))/5 ,x=(6+sqrt(51))/5
Find the zeros of -12x=3-5x^2
The zeros of -12x=3-5x^2 are x=-(-6+sqrt(51))/5 ,x=(6+sqrt(51))/5