What are the solutions to the equation t^2-2t+0.4082=0 ?

The solutions to the equation t^2-2t+0.4082=0 are t=(2+sqrt(2.3672))/2 ,t=(2-sqrt(2.3672))/2

Find the zeros of t^2-2t+0.4082=0

The zeros of t^2-2t+0.4082=0 are t=(2+sqrt(2.3672))/2 ,t=(2-sqrt(2.3672))/2

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t^{2} - 2 t + 0.4082 = 0

t = \frac{2 + 2.3672}{2}, t = \frac{2 - 2.3672}{2}

Decimal Notation

t = 1.76928 \dots, t = 0.23071 \dots

Solution steps

t^{2} - 2 t + 0.4082 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 0.4082}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 0.4082 = 2.3672

t_{1, 2} = \frac{- ( - 2 ) \pm 2.3672}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 2 ) + 2.3672}{2 \cdot 1}, t_{2} = \frac{- ( - 2 ) - 2.3672}{2 \cdot 1}

t = \frac{- ( - 2 ) + 2.3672}{2 \cdot 1} : \frac{2 + 2.3672}{2}

t = \frac{- ( - 2 ) - 2.3672}{2 \cdot 1} : \frac{2 - 2.3672}{2}

The solutions to the quadratic equation are:

t = \frac{2 + 2.3672}{2}, t = \frac{2 - 2.3672}{2}

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What are the solutions to the equation t^2-2t+0.4082=0 ?
The solutions to the equation t^2-2t+0.4082=0 are t=(2+sqrt(2.3672))/2 ,t=(2-sqrt(2.3672))/2
Find the zeros of t^2-2t+0.4082=0
The zeros of t^2-2t+0.4082=0 are t=(2+sqrt(2.3672))/2 ,t=(2-sqrt(2.3672))/2