What are the solutions to the equation 3r^2-8r+4=0 ?

The solutions to the equation 3r^2-8r+4=0 are r=2,r= 2/3

Find the zeros of 3r^2-8r+4=0

The zeros of 3r^2-8r+4=0 are r=2,r= 2/3

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3 r^{2} - 8 r + 4 = 0

r = 2, r = \frac{2}{3}

Decimal Notation

r = 2, r = 0.66666 \dots

Solution steps

3 r^{2} - 8 r + 4 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 \cdot 4 = 4

r_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 3}

Separate the solutions

r_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 3}, r_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 3}

r = \frac{- ( - 8 ) + 4}{2 \cdot 3} : 2

r = \frac{- ( - 8 ) - 4}{2 \cdot 3} : \frac{2}{3}

The solutions to the quadratic equation are:

r = 2, r = \frac{2}{3}

4 x^{2} = 60 x

3 x^{2} + 5 (2 x + 1) = 0

- 2 (x - 6)^{2} + 7 = - 23

(\frac{2}{3}) x^{2} + 5 x - 9 = 0

r^{2} + 10 r - 18 = 61

What are the solutions to the equation 3r^2-8r+4=0 ?
The solutions to the equation 3r^2-8r+4=0 are r=2,r= 2/3
Find the zeros of 3r^2-8r+4=0
The zeros of 3r^2-8r+4=0 are r=2,r= 2/3