What are the solutions to the equation 5/7 x^2-x= 2/7 ?

The solutions to the equation 5/7 x^2-x= 2/7 are x=(7+sqrt(89))/(10),x=(7-sqrt(89))/(10)

Find the zeros of 5/7 x^2-x= 2/7

The zeros of 5/7 x^2-x= 2/7 are x=(7+sqrt(89))/(10),x=(7-sqrt(89))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{5}{7} x^{2} - x = \frac{2}{7}

x = \frac{7 + 89}{10}, x = \frac{7 - 89}{10}

Decimal Notation

x = 1.64339 \dots, x = - 0.24339 \dots

Solution steps

\frac{5}{7} x^{2} - x = \frac{2}{7}

Multiply both sides by

7

5 x^{2} - 7 x = 2

Move

2

to the left side

5 x^{2} - 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

(- 7)^{2} - 4 \cdot 5 (- 2) = 89

x_{1, 2} = \frac{- ( - 7 ) \pm 89}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 89}{2 \cdot 5}, x_{2} = \frac{- ( - 7 ) - 89}{2 \cdot 5}

x = \frac{- ( - 7 ) + 89}{2 \cdot 5} : \frac{7 + 89}{10}

x = \frac{- ( - 7 ) - 89}{2 \cdot 5} : \frac{7 - 89}{10}

The solutions to the quadratic equation are:

x = \frac{7 + 89}{10}, x = \frac{7 - 89}{10}

3 r^{2} - 8 r + 4 = 0

4 x^{2} = 60 x

3 x^{2} + 5 (2 x + 1) = 0

- 2 (x - 6)^{2} + 7 = - 23

(\frac{2}{3}) x^{2} + 5 x - 9 = 0

What are the solutions to the equation 5/7 x^2-x= 2/7 ?
The solutions to the equation 5/7 x^2-x= 2/7 are x=(7+sqrt(89))/(10),x=(7-sqrt(89))/(10)
Find the zeros of 5/7 x^2-x= 2/7
The zeros of 5/7 x^2-x= 2/7 are x=(7+sqrt(89))/(10),x=(7-sqrt(89))/(10)