What are the solutions to the equation solvefor x,x^2+4x+16=0 ?

The solutions to the equation solvefor x,x^2+4x+16=0 are x=-2+2sqrt(3)i,x=-2-2sqrt(3)i

Find the zeros of solvefor x,x^2+4x+16=0

The zeros of solvefor x,x^2+4x+16=0 are x=-2+2sqrt(3)i,x=-2-2sqrt(3)i

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x, x^{2} + 4 x + 16 = 0

x = - 2 + 23 i, x = - 2 - 23 i

Solution steps

x^{2} + 4 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 16 : 43 i

x_{1, 2} = \frac{- 4 \pm 4 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4 3 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 4 3 i}{2 \cdot 1}

x = \frac{- 4 + 4 3 i}{2 \cdot 1} : - 2 + 23 i

x = \frac{- 4 - 4 3 i}{2 \cdot 1} : - 2 - 23 i

The solutions to the quadratic equation are:

x = - 2 + 23 i, x = - 2 - 23 i

x (2 x + 4) + 5 x = - 7

9 x^{2} + 18 x + 82 = 0

2.5 (x + 1)^{2} = 6 x^{2}

x^{2} - 18 - 3 x = 0

R^{2} + 7 R + 12 = 0

What are the solutions to the equation solvefor x,x^2+4x+16=0 ?
The solutions to the equation solvefor x,x^2+4x+16=0 are x=-2+2sqrt(3)i,x=-2-2sqrt(3)i
Find the zeros of solvefor x,x^2+4x+16=0
The zeros of solvefor x,x^2+4x+16=0 are x=-2+2sqrt(3)i,x=-2-2sqrt(3)i