What are the solutions to the equation x(x+1)=4 ?

The solutions to the equation x(x+1)=4 are x=(-1+sqrt(17))/2 ,x=(-1-sqrt(17))/2

Find the zeros of x(x+1)=4

The zeros of x(x+1)=4 are x=(-1+sqrt(17))/2 ,x=(-1-sqrt(17))/2

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x (x + 1) = 4

x = \frac{- 1 + 17}{2}, x = \frac{- 1 - 17}{2}

Decimal Notation

x = 1.56155 \dots, x = - 2.56155 \dots

Solution steps

x (x + 1) = 4

Expand

x (x + 1) : x^{2} + x

x^{2} + x = 4

Move

4

to the left side

x^{2} + x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 4) = 17

x_{1, 2} = \frac{- 1 \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 17}{2 \cdot 1}, x_{2} = \frac{- 1 - 17}{2 \cdot 1}

x = \frac{- 1 + 17}{2 \cdot 1} : \frac{- 1 + 17}{2}

x = \frac{- 1 - 17}{2 \cdot 1} : \frac{- 1 - 17}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 17}{2}, x = \frac{- 1 - 17}{2}

x^{2} + 8 x + 10 = 0

4 x^{2} + 32 x = - 64

- x^{2} + 10 x - 22 = 0

1 + x^{2} = (- 10)^{2}

3 x - 6 + 6 x^{2} = 0

What are the solutions to the equation x(x+1)=4 ?
The solutions to the equation x(x+1)=4 are x=(-1+sqrt(17))/2 ,x=(-1-sqrt(17))/2
Find the zeros of x(x+1)=4
The zeros of x(x+1)=4 are x=(-1+sqrt(17))/2 ,x=(-1-sqrt(17))/2