What are the solutions to the equation 2x^2-2000x+100000=0 ?

The solutions to the equation 2x^2-2000x+100000=0 are x=100(5+2sqrt(5)),x=100(5-2sqrt(5))

Find the zeros of 2x^2-2000x+100000=0

The zeros of 2x^2-2000x+100000=0 are x=100(5+2sqrt(5)),x=100(5-2sqrt(5))

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2 x^{2} - 2000 x + 100000 = 0

x = 100 (5 + 25), x = 100 (5 - 25)

Solution steps

2 x^{2} - 2000 x + 100000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2000 ) \pm ( - 2000 ) ^{2} - 4 \cdot 2 \cdot 100000}{2 \cdot 2}

(- 2000)^{2} - 4 \cdot 2 \cdot 100000 = 8005

x_{1, 2} = \frac{- ( - 2000 ) \pm 800 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2000 ) + 800 5}{2 \cdot 2}, x_{2} = \frac{- ( - 2000 ) - 800 5}{2 \cdot 2}

x = \frac{- ( - 2000 ) + 800 5}{2 \cdot 2} : 100 (5 + 25)

x = \frac{- ( - 2000 ) - 800 5}{2 \cdot 2} : 100 (5 - 25)

The solutions to the quadratic equation are:

x = 100 (5 + 25), x = 100 (5 - 25)

16 x^{2} = 40 x - 25

5 x^{2} - 10 x - 4 = 0

x^{2} + 1 2^{2} = 1 8^{2}

2 (x - 3)^{2} - 40 = 0

- x^{2} + 2 x - 3

What are the solutions to the equation 2x^2-2000x+100000=0 ?
The solutions to the equation 2x^2-2000x+100000=0 are x=100(5+2sqrt(5)),x=100(5-2sqrt(5))
Find the zeros of 2x^2-2000x+100000=0
The zeros of 2x^2-2000x+100000=0 are x=100(5+2sqrt(5)),x=100(5-2sqrt(5))