What are the solutions to the equation -0.05x^2+16x+80=0 ?

The solutions to the equation -0.05x^2+16x+80=0 are x=-40(sqrt(17)-4),x=40(4+sqrt(17))

Find the zeros of -0.05x^2+16x+80=0

The zeros of -0.05x^2+16x+80=0 are x=-40(sqrt(17)-4),x=40(4+sqrt(17))

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- 0.05 x^{2} + 16 x + 80 = 0

x = - 40 (17 - 4), x = 40 (4 + 17)

Solution steps

- 0.05 x^{2} + 16 x + 80 = 0

Multiply both sides by

100

- 5 x^{2} + 1600 x + 8000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1600 \pm 160 0 ^{2} - 4 ( - 5 ) \cdot 8000}{2 ( - 5 )}

160 0^{2} - 4 (- 5) \cdot 8000 = 40017

x_{1, 2} = \frac{- 1600 \pm 400 17}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 1600 + 400 17}{2 ( - 5 )}, x_{2} = \frac{- 1600 - 400 17}{2 ( - 5 )}

x = \frac{- 1600 + 400 17}{2 ( - 5 )} : - 40 (17 - 4)

x = \frac{- 1600 - 400 17}{2 ( - 5 )} : 40 (4 + 17)

The solutions to the quadratic equation are:

x = - 40 (17 - 4), x = 40 (4 + 17)

x, z = - x^{2} - y^{2}

x^{2} - (3 + 1) x + 3 = 0

- 6 x^{2} + 9 x + 24 = 0

- 4 m^{2} - 12 m + 3 = 0

x^{2} - 20 = - 8 x

What are the solutions to the equation -0.05x^2+16x+80=0 ?
The solutions to the equation -0.05x^2+16x+80=0 are x=-40(sqrt(17)-4),x=40(4+sqrt(17))
Find the zeros of -0.05x^2+16x+80=0
The zeros of -0.05x^2+16x+80=0 are x=-40(sqrt(17)-4),x=40(4+sqrt(17))