What are the solutions to the equation x^2-(sqrt(3)+1)x+sqrt(3)=0 ?

The solutions to the equation x^2-(sqrt(3)+1)x+sqrt(3)=0 are x=sqrt(3),x=1

Find the zeros of x^2-(sqrt(3)+1)x+sqrt(3)=0

The zeros of x^2-(sqrt(3)+1)x+sqrt(3)=0 are x=sqrt(3),x=1

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x^{2} - (3 + 1) x + 3 = 0

x = 3, x = 1

Solution steps

x^{2} - (3 + 1) x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 - 1 ) \pm ( - 3 - 1 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 3 - 1)^{2} - 4 \cdot 1 \cdot 3 = 3 - 1

x_{1, 2} = \frac{- ( - 3 - 1 ) \pm ( 3 - 1 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 - 1 ) + 3 - 1}{2 \cdot 1}, x_{2} = \frac{- ( - 3 - 1 ) - ( 3 - 1 )}{2 \cdot 1}

x = \frac{- ( - 3 - 1 ) + 3 - 1}{2 \cdot 1} : 3

x = \frac{- ( - 3 - 1 ) - ( 3 - 1 )}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 3, x = 1

- 6 x^{2} + 9 x + 24 = 0

- 4 m^{2} - 12 m + 3 = 0

x^{2} - 20 = - 8 x

- x^{2} + 2 x = - 3

(x + 1)^{2} - \frac{x + 1}{2} = 18

What are the solutions to the equation x^2-(sqrt(3)+1)x+sqrt(3)=0 ?
The solutions to the equation x^2-(sqrt(3)+1)x+sqrt(3)=0 are x=sqrt(3),x=1
Find the zeros of x^2-(sqrt(3)+1)x+sqrt(3)=0
The zeros of x^2-(sqrt(3)+1)x+sqrt(3)=0 are x=sqrt(3),x=1